Question

The spectator ion in the equation is


a. (aq)
b. Cu(s)
c.
d. Mg(s)
e. (aq)

Answer 1

I can't see the reaction — the chemical formulas are missing from your question. Please paste the full equation (or a clear photo) so I can identify the spectator ion.

Meanwhile, here’s how to find it yourself:

1. Write the balanced molecular equation.
2. Break all soluble ionic compounds into their ions (complete ionic equation). Keep solids, liquids and gases as formulas.
3. Cancel any ions that appear unchanged on both sides — those are the spectator ions.
4. The remaining species give the net ionic equation.

Example: CuSO4(aq) + Mg(s) → MgSO4(aq) + Cu(s)
- Ionic form: Cu2+(aq) + SO4^2−(aq) + Mg(s) → Mg2+(aq) + SO4^2−(aq) + Cu(s)
- SO4^2−(aq) appears unchanged on both sides, so the spectator ion is SO4^2−(aq).

Send the exact equation and I’ll identify the spectator ion for you.