Question

On a coordinate plane, line M N goes through points (2, 3) and (negative 3, 2). Point K is at (3, negative 3).
Which point could be on the line that is perpendicular to Line M N and passes through point K?

(0, −12)
(2, 2)
(4, 8)
(5, 13)

Answer 1

Slope of MN = (3 − 2)/(2 − (−3)) = 1/5.
Perpendicular slope = −5. Line through K(3, −3): y + 3 = −5(x − 3) → y = −5x + 12.
Check points: for x=2, y = −5(2)+12 = 2. So (2, 2) is on the perpendicular line.