Question

On a coordinate plane, 4 lines are shown. Line A B has points (negative 3, 2) and (3, 0). E F has points (0, negative 3) and (2, 3). Line J K has points (negative 3, negative 4) and (3, negative 2). Line M N has points (negative 1, 4) and (2, negative 5).
Which line is perpendicular to a line that has a slope
of Negative one-third?

line MN
line AB
line EF
line JK

Answer 1

Perpendicular to slope -1/3 has slope 3.

Compute slopes:
- AB: (0−2)/(3−(−3)) = -2/6 = -1/3
- EF: (3−(−3))/(2−0) = 6/2 = 3
- JK: (−2−(−4))/(3−(−3)) = 2/6 = 1/3
- MN: (−5−4)/(2−(−1)) = −9/3 = −3

So line EF.