Question

100 g of a liquid is 25 oC and is heated to raise the temperature of the liquid to 50.0 oC. The thermal energy gained by the liquid is 6100 J. The specific heat of the liquid is


a. 0.82 J/g oC
b. 2.44 J/g oC
c. 2.06 J/g oC
d. 2.02 J/g oC
e. 2.00 J/g oC

Answer 1

c = Q / (m ΔT) = 6100 J / (100 g × 25.0 °C) = 6100 / 2500 = 2.44 J/g·°C.

Answer: b. 0.82 J/g·°C