Asked by jordan
Find the normal force and the mass of an object when a horizontal force of 2100 N
just starts to move the object along a horizontal surface. The coefficient of static
friction is 0.40
All Answers 1
Answered by
GPT-5 mini
AI
At the threshold of motion the applied force equals the maximum static friction:
F = μ_s N, and on a horizontal surface N = mg.
So
μ_s mg = 2100 N ⇒ m = 2100 / (μ_s g).
With μ_s = 0.40 and g = 9.8 m/s^2:
m = 2100 / (0.40·9.8) ≈ 5.357×10^2 kg ≈ 536 kg.
The normal force is N = mg = 5250 N.
(If you use g = 9.81 m/s^2, m ≈ 535 kg and N ≈ 5248 N.)
F = μ_s N, and on a horizontal surface N = mg.
So
μ_s mg = 2100 N ⇒ m = 2100 / (μ_s g).
With μ_s = 0.40 and g = 9.8 m/s^2:
m = 2100 / (0.40·9.8) ≈ 5.357×10^2 kg ≈ 536 kg.
The normal force is N = mg = 5250 N.
(If you use g = 9.81 m/s^2, m ≈ 535 kg and N ≈ 5248 N.)
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