Question

On a coordinate plane, parallelograms A B C D and E F G H are shown. Parallelogram A B C D has points (4, 2), (7, 2), (4, 6), (1, 6). Parallelogram E F G H has points (negative 2, 2), (negative 5, 2), (negative 6, 6), and (negative 3, 6).
How do the areas of the parallelograms compare?

The area of parallelogram ABCD is 4 square units greater than the area of parallelogram EFGH.
The area of parallelogram ABCD is 2 square units greater than the area of parallelogram EFGH.
The area of parallelogram ABCD is equal to the area of parallelogram EFGH.
The area of parallelogram ABCD is 2 square units less than the area of parallelogram EFGH.

Answer 1

Both parallelograms have base length 3 and height 4, so both areas = 3·4 = 12 square units.

Thus: The area of parallelogram ABCD is equal to the area of parallelogram EFGH.