Question

On a coordinate plane, rhombus D E F G is shown. It has points (1, 4), (4, 0), (1, negative 4), and (negative 2, 0).
The vertices of rhombus DEFG are D(1, 4), E(4, 0), F(1, –4), and G(–2, 0).

What is the perimeter of the rhombus?

units

Answer 1

Distance DE = sqrt[(4−1)^2 + (0−4)^2] = sqrt(3^2 + (−4)^2) = sqrt(25) = 5. All sides equal, so perimeter = 4·5 = 20.

20 units