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A construction crew is pouring a concrete foundation. They complete 1/4 of the total job on the first day. On the second day, they pour concrete for 2/3 of the remaining work. On the third day, the crew works for 4 hours and completes the final 1/5 of the original total job, plus an extra 2 square feet due to increased efficiency.What is the total size of the concrete foundation in square feet, and how many square feet did the crew complete on the second day?
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Let the total be T ft².
Day 1: (1/4)T done, remaining = (3/4)T.
Day 2: (2/3) of remaining = (2/3)(3/4)T = (1/2)T done, leaving (1/4)T.
Day 3: they actually finish (1/5)T + 2, which equals the remaining (1/4)T.
So (1/4)T = (1/5)T + 2 => (1/20)T = 2 => T = 40 ft².
Second day amount = (1/2)T = 20 ft².
Answer: total = 40 ft²; second day = 20 ft².
Day 1: (1/4)T done, remaining = (3/4)T.
Day 2: (2/3) of remaining = (2/3)(3/4)T = (1/2)T done, leaving (1/4)T.
Day 3: they actually finish (1/5)T + 2, which equals the remaining (1/4)T.
So (1/4)T = (1/5)T + 2 => (1/20)T = 2 => T = 40 ft².
Second day amount = (1/2)T = 20 ft².
Answer: total = 40 ft²; second day = 20 ft².
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