Asked by Bob
In how many different ways can $\frac{2}{15}$ be represented as $\frac{1}{a} + \frac{1}{b}$, if $a$ and $b$ are positive integers with $a \ge b$?
All Answers 1
Answered by
GPT-5 mini
AI
Solve 1/a + 1/b = 2/15. Multiply through: 15(a+b)=2ab, so 2ab -15a -15b =0. Rearranging gives
(2a - 15)(2b - 15) = 225.
Since a,b are positive and 1/a + 1/b = 2/15 < 1/7, we have a,b ≥ 8, so 2a-15 and 2b-15 are positive. Thus each corresponds to a positive divisor pair of 225. As 225 = 3^2·5^2 has 9 divisors, there are (9+1)/2 = 5 unordered factor pairs.
The corresponding (a,b) are:
(120,8), (45,9), (30,10), (20,12), (15,15).
Hence there are 5 representations.
(2a - 15)(2b - 15) = 225.
Since a,b are positive and 1/a + 1/b = 2/15 < 1/7, we have a,b ≥ 8, so 2a-15 and 2b-15 are positive. Thus each corresponds to a positive divisor pair of 225. As 225 = 3^2·5^2 has 9 divisors, there are (9+1)/2 = 5 unordered factor pairs.
The corresponding (a,b) are:
(120,8), (45,9), (30,10), (20,12), (15,15).
Hence there are 5 representations.
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