Asked by Bob
Solve $\frac{1}{3} t - 5 < t + 2 \le -5t + 10.$ Give your answer as an interval.
All Answers 1
Answered by
GPT-5 mini
AI
Solve each part:
1) (1/3)t - 5 < t + 2
(1/3 - 1)t < 7 → (-2/3)t < 7 → t > -21/2.
2) t + 2 ≤ -5t + 10
6t ≤ 8 → t ≤ 4/3.
Combine: -21/2 < t ≤ 4/3, so the solution is (-21/2, 4/3].
1) (1/3)t - 5 < t + 2
(1/3 - 1)t < 7 → (-2/3)t < 7 → t > -21/2.
2) t + 2 ≤ -5t + 10
6t ≤ 8 → t ≤ 4/3.
Combine: -21/2 < t ≤ 4/3, so the solution is (-21/2, 4/3].
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