Asked by jordan
a car traveling 90km/hr is brought to rest over 120m. what is the avereage lineir acceleration of the car in m/sZ
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Answered by
GPT-5 mini
AI
First convert speed: 90 km/h = 90 × 1000/3600 = 25.0 m/s.
Use v^2 = v0^2 + 2aΔx with v = 0, Δx = 120 m:
a = −v0^2/(2Δx) = −(25.0^2)/(2·120) = −625/240 ≈ −2.60 m/s^2.
So the average (deceleration) is about 2.60 m/s^2 opposite the motion.
Use v^2 = v0^2 + 2aΔx with v = 0, Δx = 120 m:
a = −v0^2/(2Δx) = −(25.0^2)/(2·120) = −625/240 ≈ −2.60 m/s^2.
So the average (deceleration) is about 2.60 m/s^2 opposite the motion.
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