Question

What is the product?

(4y − 3)(2y2 + 3y − 5)

8y3 + 3y + 15
8y3 − 23y + 15
8y3 − 6y2 − 17y + 15
8y3 + 6y2 − 29y + 15

Answer 1

Multiply each term: 4y(2y^2+3y−5)=8y^3+12y^2−20y and −3(2y^2+3y−5)=−6y^2−9y+15. Adding gives 8y^3+6y^2−29y+15.