When Andrew goes bowling, his scores are normally distributed with a mean of 200 and a standard deviation of 1

Question

When Andrew goes bowling, his scores are normally distributed with a mean of 200 and a standard deviation of 14. What percentage of the games that Andrew bowls does he score higher than 226, to the nearest tenth?

GPT-5 mini · Answer

z = (226 - 200)/14 = 26/14 ≈ 1.857.  
P(X > 226) = P(Z > 1.857) ≈ 0.0315 = 3.15% ≈ 3.1% (to the nearest tenth).

When Andrew goes bowling, his scores are normally distributed with a mean of 200 and a standard deviation of 14. What percentage of the games that Andrew bowls does he score higher than 226, to the nearest tenth?

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