Question

Iliana multiplied 3p – 7 and 2p2 – 3p – 4. Her work is shown in the table.

The expression (3 p minus 7)(2 p squared minus 3 p minus 4) is shown above a table with 3 columns and 2 rows. First column is labeled 2 p squared, second column is labeled negative 3 p, the third column is labeled negative 4. First row is labeled 3 p with entries 6 p cubed, negative 9 p squared, negative 12 p. Second row is labeled negative 7 with entries negative 14 p squared, 21 p, 28.
Which is the product?

6p3 + 23p2 + 9p + 28
6p3 – 23p2 – 9p + 28
6p3 – 23p2 + 9p + 28
6p3 + 23p2 – 9p + 28

Answer 1

Multiply each column and combine like terms:
6p^3 + (−9p^2 − 14p^2) + (−12p + 21p) + 28 = 6p^3 − 23p^2 + 9p + 28.

So the product is 6p^3 − 23p^2 + 9p + 28 (third choice).