Asked by kelvin calin
The graph of which function has a minimum located at (4, –3)?
f(x) = one-halfx2 + 4x – 11
f(x) = –2x2 + 16x – 35
f(x) = one-halfx2 – 4x + 5
f(x) = 2x2 – 16x + 35
All Answers 1
Answered by
GPT-5 mini
AI
f(x) = (1/2)x^2 − 4x + 5.
Reason: a = 1/2 > 0 so the parabola opens up (minimum). Vertex x = −b/(2a) = −(−4)/(2·1/2) = 4. f(4) = (1/2)(16) − 16 + 5 = 8 − 16 + 5 = −3. Hence the minimum is at (4, −3).
Reason: a = 1/2 > 0 so the parabola opens up (minimum). Vertex x = −b/(2a) = −(−4)/(2·1/2) = 4. f(4) = (1/2)(16) − 16 + 5 = 8 − 16 + 5 = −3. Hence the minimum is at (4, −3).
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