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A snowstorm took place during the weekend. Meteorologists tracked the total amount of snowfall for the storm. For the first 2 hours, it snowed at a rate of 1 inch per hour. The snow stopped for an hour and a half, then resumed at a
rate of 1.5 inches per hour for the next 3 hours. Based on this information, what scale would work best for representing the data on the x-axis? (1 point)
2 hrs
3 hrs
5 hrs
0.5 hrs
y
2.5-
2.25
2
1.75
1.5
1.25
1
0.75
0.5-
0.25
3 5 7 9 11 13 15 17 19 21 23 25
On Friday, Kaitlyn went to the park to work out. She started with a slow jog at a constant rate for five minutes. She then increased her speed to a faster, constant pace for seven minutes. She took a three-minute break, then ran for
another 7.5 minutes at a constant pace to finish her two-mile run. She rested for the remainder of the time.
(2 points)
01
During what domain interval will she be at 1.25 miles?
VI
All Answers 1
Answered by
GPT-5 mini
AI
1) 0.5 hrs — the storm lasted 6.5 hours total (2 + 1.5 + 3), so 0.5-hour increments let you mark 1.5 and 6.5 easily.
2) I need either the graph or Kaitlyn’s running speeds to answer exactly. Method: let distances be d1 = v1·5, d2 = v2·7, d3 = v3·7.5 with d1+d2+d3 = 2. Solve for v’s (or use the graph) and find the time t where cumulative distance = 1.25.
If you assume she ran at one constant pace for all running segments (v1 = v2 = v3), then total running time = 5 + 7 + 7.5 = 19.5 min, pace = 2/19.5 ≈ 0.10256 mi/min, so 1.25 mi occurs at t = 1.25/0.10256 ≈ 12.19 minutes — i.e., during the 12–15 minute interval (her break).
If you can upload the graph or give the speeds (or state that the two running paces are equal or different), I’ll give the exact domain interval.
2) I need either the graph or Kaitlyn’s running speeds to answer exactly. Method: let distances be d1 = v1·5, d2 = v2·7, d3 = v3·7.5 with d1+d2+d3 = 2. Solve for v’s (or use the graph) and find the time t where cumulative distance = 1.25.
If you assume she ran at one constant pace for all running segments (v1 = v2 = v3), then total running time = 5 + 7 + 7.5 = 19.5 min, pace = 2/19.5 ≈ 0.10256 mi/min, so 1.25 mi occurs at t = 1.25/0.10256 ≈ 12.19 minutes — i.e., during the 12–15 minute interval (her break).
If you can upload the graph or give the speeds (or state that the two running paces are equal or different), I’ll give the exact domain interval.
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