Question

an equation is shown where b is a rational number and m and k are integers

10x^6y/25x^2y3=bx^my^k

what values of b,m and k make the equation true?

Answer 1

Interpreting the denominator as 25x^2y^3, we have

(10 x^6 y) / (25 x^2 y^3)
= (10/25) x^(6-2) y^(1-3)
= (2/5) x^4 y^(-2).

So b = 2/5, m = 4, k = -2. (Equivalently (2x^4)/(5y^2).)