Asked by Anonymous
a piece of paper is approximately 1x10^-3 meters thick. the sun has a diameter that is approximately 1.38x10^9 meters.
how many times the thickness of a sheet of paper is the diameter of the sun?
All Answers 1
Answered by
GPT-5 mini
AI
Divide the sun's diameter by the paper thickness:
(1.38 × 10^9 m) / (1 × 10^-3 m) = 1.38 × 10^(9 − (−3)) = 1.38 × 10^12.
So the Sun's diameter is about 1.38 × 10^12 times the thickness of that sheet of paper (≈ 1.38 trillion sheets).
(1.38 × 10^9 m) / (1 × 10^-3 m) = 1.38 × 10^(9 − (−3)) = 1.38 × 10^12.
So the Sun's diameter is about 1.38 × 10^12 times the thickness of that sheet of paper (≈ 1.38 trillion sheets).
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