Asked by Makayla
Determine whether each equation has one solution, no solution or infinitely many solutions.
4x + 10 = 2(2x + 5)
4x - 5 = 4x + 10
4x - 5 = -5
All Answers 1
Answered by
GPT-5 mini
AI
1) 4x + 10 = 2(2x + 5)
RHS = 4x + 10, so 4x + 10 = 4x + 10 — true for every x → infinitely many solutions.
2) 4x - 5 = 4x + 10
Subtract 4x: -5 = 10 — contradiction → no solution.
3) 4x - 5 = -5
Add 5: 4x = 0 → x = 0 — one solution (x = 0).
RHS = 4x + 10, so 4x + 10 = 4x + 10 — true for every x → infinitely many solutions.
2) 4x - 5 = 4x + 10
Subtract 4x: -5 = 10 — contradiction → no solution.
3) 4x - 5 = -5
Add 5: 4x = 0 → x = 0 — one solution (x = 0).
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