Question

A pastry chef is creating a chocolate dessert in the shape of a triangular pyramid. The pyramid has a base of 5 in., the height of the base is 4.3 in., and the slant height is 6 in. Use the correct formula to find the surface area of the chocolate pyramid. (1 point)
Responses

52.25 in.2

52.25 in. squared

58.25 in.2

58.25 in. squared

47.25 in.2

47.25 in. squared

55.75 in.2

Answer 1

Surface area = base area + 3 lateral faces.

Base area = 1/2 · 5 · 4.3 = 10.75 in^2.
Each lateral face area = 1/2 · 5 · 6 = 15 in^2, so 3 faces = 45 in^2.
Total surface area = 10.75 + 45 = 55.75 in^2.

Answer: 55.75 in.^2