Question

What is the formula for finding the surface area of a regular triangular pyramid?(1 point)
Responses

SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√

cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root - no response given

SA=12ab+3(12lb)

cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren - no response given

SA=2(wl+lh+hw)

cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren - incorrect

SA=a2+2aa24+h2−−−−−−√

Answer 1

Surface area = base area + 3 × (area of one lateral triangle).

If a = side length of the equilateral base and s = slant height, then
SA = (√3 / 4) a^2 + (3/2) a s.