Question

Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
Responses

Book B will require less wrapping paper because its surface area is 0.5 in.2
less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 0 point 5 in. power 2 less than the surface area of Book A.

Book A will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book B.
Book A will require less wrapping paper because its surface area is 1 point 5 in. power 2 less than the surface area of Book B.

Book B will require less wrapping paper because its surface area is 1.5 in.2
less than the surface area of Book A.
Book B will require less wrapping paper because its surface area is 1 point 5 in. power 2 less than the surface area of Book A.

Book A will require less wrapping paper because its surface area is 32.75 in.2
less than the surface area of Book B.

Answer 1

Surface area = 2(lw + lh + wh).

Book A: 2(6.5·1 + 6.5·8.5 + 1·8.5) = 2(6.5 + 55.25 + 8.5) = 2(70.25) = 140.5 in².
Book B: 2(5.5·2 + 5.5·8 + 2·8) = 2(11 + 44 + 16) = 2(71) = 142 in².

Book A requires less wrapping paper; its surface area is 1.5 in² less than Book B.