Question

A loaded dogsled has a mass of 400kg and is being pulled across a horizontal, paced snow surface at a velocity of 4.0m/s (N). Suddenly, the harness separates from the sled. If the coefficient of kinetic friction for the sled on the snow is 0.0500, how far will the sled coast before stopping?

Answer 1

Solve this equation for X:

Initial kinetic energy = work done aqainst friction

(1/2) M*Vo^2 = M*g *Uk * X

M cancels out. Uk = 0.050

Answer 2

4 m

Answer 3

This needs the kinematic equation - vf^2 = vi^2 + 2 x a x d
vf = 0 ( since he'll stop)
vi = 4.0
a = ( must be found)
d = ???? ( for now)


to find a

a is decelleration, because their is no applied force.

fnet = -uk x Ffk
m x a = -0.0500 x m x g
since there are m's cross them out.
a = -0.0500 x g
a = -0.49 m/s^2

fill in to the kinematic equation

vf^2 = vi ^2 + 2 x a x d
0 = 16 + 2 x -0.49 x d
d = -16.32
rounded (16m)