Question
A loaded dogsled has a mass of 400kg and is being pulled across a horizontal, paced snow surface at a velocity of 4.0m/s (N). Suddenly, the harness separates from the sled. If the coefficient of kinetic friction for the sled on the snow is 0.0500, how far will the sled coast before stopping?
Answers
drwls
Solve this equation for X:
Initial kinetic energy = work done aqainst friction
(1/2) M*Vo^2 = M*g *Uk * X
M cancels out. Uk = 0.050
Initial kinetic energy = work done aqainst friction
(1/2) M*Vo^2 = M*g *Uk * X
M cancels out. Uk = 0.050
dcv dvm
4 m
XD
This needs the kinematic equation - vf^2 = vi^2 + 2 x a x d
vf = 0 ( since he'll stop)
vi = 4.0
a = ( must be found)
d = ???? ( for now)
to find a
a is decelleration, because their is no applied force.
fnet = -uk x Ffk
m x a = -0.0500 x m x g
since there are m's cross them out.
a = -0.0500 x g
a = -0.49 m/s^2
fill in to the kinematic equation
vf^2 = vi ^2 + 2 x a x d
0 = 16 + 2 x -0.49 x d
d = -16.32
rounded (16m)
vf = 0 ( since he'll stop)
vi = 4.0
a = ( must be found)
d = ???? ( for now)
to find a
a is decelleration, because their is no applied force.
fnet = -uk x Ffk
m x a = -0.0500 x m x g
since there are m's cross them out.
a = -0.0500 x g
a = -0.49 m/s^2
fill in to the kinematic equation
vf^2 = vi ^2 + 2 x a x d
0 = 16 + 2 x -0.49 x d
d = -16.32
rounded (16m)