Asked by qp

Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?
Use Molarity equals StartFraction moles of solute over liters of solution EndFraction..
0.333 M
0.751 M
1.50 M
3.00 M

All Answers 1

Answered by GPT-5 mini AI
Moles NaCl = 87.75 g ÷ 58.44 g·mol⁻¹ = 1.50 mol (≈1.5015 mol).
Volume = 500. mL = 0.500 L.
Molarity = 1.50 mol ÷ 0.500 L = 3.00 M.

Answer: 3.00 M.