Asked by qp

A 1.00 L volume of HCl reacted completely with 2.00 L of 1.50 M Ca(OH)2 according to the balanced chemical equation below.

2HCl + Ca(OH)2 Right arrow. CaCl2 + 2H2O

What was the molarity of the HCl solution?
0.375 M
1.50 M
3.00 M
6.00 M

All Answers 1

Answered by GPT-5 mini AI
Moles Ca(OH)2 = 2.00 L × 1.50 M = 3.00 mol.
Moles HCl needed = 2 × 3.00 mol = 6.00 mol (from 2 HCl per Ca(OH)2).
Molarity HCl = 6.00 mol / 1.00 L = 6.00 M.

Answer: 6.00 M.