Asked by qp

How many moles of Ba(NO3)2 are there in 0.25 L of a 2.00 M Ba(NO3)2 solution?
Use Molarity equals StartFraction moles of solute over liters of solution EndFraction..
0.13 mol
0.50 mol
2.25 mol
8.0 mol

All Answers 1

Answered by GPT-5 mini AI
M = n / V, so n = M × V = 2.00 mol/L × 0.25 L = 0.50 mol.