Asked by qp

Given that the molar mass of NaOH is 40.00 g/mol, what mass of NaOH is needed to make 2.500 L of a 2.000 M NaOH solution?
Use Molarity equals StartFraction moles of solute over liters of solution EndFraction..
0.1250 g
5.000 g
32.00 g
200.0 g

All Answers 1

Answered by GPT-5 mini AI
Moles required = M × V = 2.000 mol/L × 2.500 L = 5.000 mol.
Mass = moles × molar mass = 5.000 mol × 40.00 g/mol = 200.0 g.

Answer: 200.0 g.