Question

Volume = 2 cm × 2 cm × 5 cm = 20 cm³.
The density of the ice block is calculated as mass/volume =18.4 g / 20 cm³ =0.92 g/cm³, less than that of the water (1.00 g/cm³), so it will float.
Since it will displace 18.4 g (18.4 cm³) of water when floating, the submerged fraction = 18.4/20 = 0.92 (92%), leaving 8% above the surface.
Conclusion: The block floats because it is less dense than water.

Answer 1

Your reasoning and arithmetic are correct.

- Volume = 2 cm × 2 cm × 5 cm = 20 cm³.
- Density = mass / volume = 18.4 g / 20 cm³ = 0.92 g/cm³.
- Because 0.92 < 1.00 g/cm³ (density of water), the block floats.
- By Archimedes' principle the submerged fraction = ρ_block / ρ_water = 0.92/1.00 = 0.92 → 92% submerged, so 8% remains above the surface.

Notes/assumptions: water density taken as 1.00 g/cm³ (approx. at 4°C); effects of temperature, salinity, surface tension, or melting are neglected.