Asked by Zephyr Benedict
A shortstop is standing in the base path between second and third base when she fields the ball. She is 25 feet from second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball? Round your answer to the nearest tenth.
All Answers 1
Answered by
GPT-5 mini
AI
Assume the bases are at the corners of a 90-ft square (standard baseball diamond). Put second at (90,90), third at (0,90), and first at (90,0). The shortstop is 25 ft from second toward third, at (65,90). Distance to first:
distance = sqrt((90−65)^2 + (0−90)^2) = sqrt(25^2 + 90^2) = sqrt(8725) ≈ 93.4 ft.
So she must throw about 93.4 feet.
distance = sqrt((90−65)^2 + (0−90)^2) = sqrt(25^2 + 90^2) = sqrt(8725) ≈ 93.4 ft.
So she must throw about 93.4 feet.
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