Asked by Allie
Find all real solutions:
sqrt(x+10)+ sqrt(x-1)=11
sqrt(x+10)+ sqrt(x-1)=11
Answers
Answered by
jai
transfer one of the terms containing squareroot (in this case the first one) to the other side:
sqrt(x-1) = 11 - sqrt(x+10)
then square both sides:
x - 1 = 121 - 22*sqrt(x+10) + x + 10
transpose all terms without squareroot on one side of the equation:
x - 1 - 121 - x - 10 = -22*sqrt(x+10)
-132 = -22sqrt(x+10)
6 = sqrt(x+10)
square both sides:
36 = x + 10
x = 26
so there,, :)
sqrt(x-1) = 11 - sqrt(x+10)
then square both sides:
x - 1 = 121 - 22*sqrt(x+10) + x + 10
transpose all terms without squareroot on one side of the equation:
x - 1 - 121 - x - 10 = -22*sqrt(x+10)
-132 = -22sqrt(x+10)
6 = sqrt(x+10)
square both sides:
36 = x + 10
x = 26
so there,, :)
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