Question

Drag and drop the integers to fill in the quadratic formula and the values for a, b, and c for the following equation 2x2+3x−8=0

Answer 1

For 2x^2 + 3x − 8 = 0:

- a = 2
- b = 3
- c = −8

Quadratic formula: x = [−b ± √(b^2 − 4ac)] / (2a)

Substituting the integers: x = [−3 ± √(3^2 − 4·2·(−8))] / (2·2) = [−3 ± √73] / 4

So the solutions are x = (−3 + √73)/4 and x = (−3 − √73)/4.