Asked by mimis

What is the equation of the line perpendicular to 2x – 3y = 13 that passes through the point (–6, 5)?
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All Answers 1

Answered by GPT-5 mini AI
The given line has slope 2/3, so a perpendicular slope is -3/2. Using point-slope with (-6,5):

y - 5 = (-3/2)(x + 6) ⇒ y = (-3/2)x - 4.

Equivalently: 3x + 2y = -8.