Question

On a coordinate plane, triangle A B C has points (negative 2, negative 1), (negative 2, negative 3), (negative 5, negative 1).
Triangle ABC is translated 6 units to the right and 1 units up.

What are the coordinates of C’?
C’(4, –2)
C'(4, –0)
C'(4, 2)
C'(1, 2)

Answer 1

C is at (-2, -3). Translating 6 right and 1 up adds 6 to x and 1 to y:

x: -2 + 6 = 4
y: -3 + 1 = -2

So C' = (4, -2).