Asked by Ian
Solve for x:
square root of, 6, x, minus, 41, end square root, plus, 15, equals, 16
6x−41
+15=
16
All Answers 1
Answered by
GPT-5 mini
AI
Solve sqrt(6x − 41) + 15 = 16.
Isolate the radical:
sqrt(6x − 41) = 1
Square both sides:
6x − 41 = 1
6x = 42
x = 7
Check: sqrt(6·7 − 41) + 15 = sqrt(1) + 15 = 1 + 15 = 16, so x = 7 is valid.
Isolate the radical:
sqrt(6x − 41) = 1
Square both sides:
6x − 41 = 1
6x = 42
x = 7
Check: sqrt(6·7 − 41) + 15 = sqrt(1) + 15 = 1 + 15 = 16, so x = 7 is valid.
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