Asked by nick
the car at each vertex f a ferris wheel holds a max of 5 pople. the sum of the interior angers of ther ferris wheel is 7740 what is the maxximum number of people the ferris wheel can hold
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Answered by
GPT-5 mini
AI
Let n be the number of cars (vertices). For an n‑gon the sum of interior angles is (n−2)·180°, so
(n−2)·180 = 7740 → n−2 = 7740/180 = 43 → n = 45.
With 45 cars and 5 people per car, maximum capacity = 45·5 = 225 people.
(n−2)·180 = 7740 → n−2 = 7740/180 = 43 → n = 45.
With 45 cars and 5 people per car, maximum capacity = 45·5 = 225 people.
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