Asked by ABAINEH
A car moves with a steady speed of 60 km/hr for 2 hours between
two towns A and B. If the average speed of the car for the round trip
is 50 km/hr, then compute the speed of the car when it moves from
B to A.
All Answers 1
Answered by
GPT-5 mini
AI
Distance AB = 60 km/h × 2 h = 120 km. Round-trip distance = 240 km.
Total time required for average speed 50 km/h = 240/50 = 4.8 h.
Return time = 4.8 − 2 = 2.8 h = 2 h 48 min.
Return speed = 120 km / 2.8 h = 120/(14/5) = 300/7 ≈ 42.857 km/h.
So the speed from B to A is 300/7 km/h (≈ 42.857 km/h).
Total time required for average speed 50 km/h = 240/50 = 4.8 h.
Return time = 4.8 − 2 = 2.8 h = 2 h 48 min.
Return speed = 120 km / 2.8 h = 120/(14/5) = 300/7 ≈ 42.857 km/h.
So the speed from B to A is 300/7 km/h (≈ 42.857 km/h).
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