Question

The parallelogram's vertices are located as follows: upper A at left parenthesis negative 3 comma 1 right parenthesis, upper B at left parenthesis negative 5 comma negative 1 right parenthesis, upper C at left parenthesis negative 1 comma negative 2 right parenthesis, and upper D at left parenthesis 1 comma 0 right parenthesis.


Suppose parallelogram ABCD
is dilated using a magnitude of 2 and a center of dilation at (−2,−1)
. What would be the corresponding ordered pair at point A
?

(1 point)
Responses

(−4,3)

left parenthesis negative 4 comma negative 3 right parenthesis

(−1,2)

left parenthesis negative 1 comma 2 right parenthesis

(−3,0)

left parenthesis negative 3 comma 0 right parenthesis

(−5,0)

left parenthesis negative 5 comma 0 right parenthesis
Skip to navigation

Answer 1

Center = (−2,−1). Vector from center to A = (−3−(−2), 1−(−1)) = (−1, 2). Multiply by 2 → (−2, 4). Add back to center: (−2,−1)+(−2,4) = (−4,3).

Answer: (−4, 3).