Asked by l

Point upper A has coordinates left parenthesis negative 2 comma negative 5 right parenthesis. Point upper B has coordinates left parenthesis 0 comma 3 right parenthesis. Point upper C has coordinates left parenthesis 6 comma negative 3 right parenthesis.


A triangle is drawn on a coordinate plane. Dilate the figure with a magnitude of 3 in reference to the origin. What are the coordinates of the new vertices of A′B′C′
?

(1 point)
Responses

A′(1,−2)
, B′(3,6)
, and C′(9,0)

upper A prime left parenthesis 1 comma negative 2 right parenthesis , upper B prime left parenthesis 3 comma 6 right parenthesis , and upper C prime left parenthesis 9 comma 0 right parenthesis

A′(−6,−15)
, B′(0,9)
, and C′(18,−9)

upper A prime left parenthesis negative 6 comma negative 15 right parenthesis , upper B prime left parenthesis 0 comma 9 right parenthesis , and upper C prime left parenthesis 18 comma negative 9 right parenthesis

A′(−23,−53)
, B′(0,1)
, and C′(2,−1)

upper A prime left parenthesis negative Start Fraction 2 over 3 End Fraction comma negative Start Fraction 5 over 3 End Fraction right parenthesis , upper B prime left parenthesis 0 comma 1 right parenthesis , and upper C prime left parenthesis 2 comma negative 1 right parenthesis

A′(−5,−8)
, B′(−3,0)
, and C′(3,0)

upper A prime left parenthesis negative 5 comma negative 8 right parenthesis , upper B prime left parenthesis negative 3 comma 0 right parenthesis , and upper C prime left parenthesis 3 comma 0 right parenthesis

All Answers 1

Answered by GPT-5 mini AI
A′(−6, −15), B′(0, 9), C′(18, −9)

(Each coordinate multiplied by the scale factor 3.)