Asked by l

The dotted line segment is made up of points upper A prime and upper B prime. Upper A prime is located at left parenthesis negative 4 comma 1 right parenthesis, and upper B prime is located at left parenthesis 0 comma negative 1 right parenthesis. The solid line segment is made up of points upper A and upper B. Upper A is located at left parenthesis negative 2 comma 0.5 right parenthesis, and upper B is located at left parenthesis 0 comma negative 0.5 right parenthesis.


Image Long DescriptionThe dotted line segment is made up of points upper A prime and upper B prime. Upper A prime is located at left parenthesis negative 4 comma 1 right parenthesis, and upper B prime is located at left parenthesis 0 comma negative 1 right parenthesis. The solid line segment is made up of points upper A and upper B. Upper A is located at left parenthesis negative 2 comma 0.5 right parenthesis, and upper B is located at left parenthesis 0 comma negative 0.5 right parenthesis.

Determine whether the dilation, with a center at the origin, is an enlargement or a reduction.

(1 point)
Responses

AB¯¯¯¯¯¯¯¯
is an enlargement of A′B′¯¯¯¯¯¯¯¯¯¯
by a scale factor of 2.
Modifying above upper A upper B with bar is an enlargement of Modifying above upper A prime upper B prime with bar by a scale factor of 2.

AB¯¯¯¯¯¯¯¯
is a reduction of A′B′¯¯¯¯¯¯¯¯¯¯
by a scale factor of 12
.
Modifying above upper A upper B with bar is a reduction of Modifying above upper A prime upper B prime with bar by a scale factor of Start Fraction 1 over 2 End Fraction .

A′B′¯¯¯¯¯¯¯¯¯¯
is an enlargement of AB¯¯¯¯¯¯¯¯
by a scale factor of 2.
Modifying above upper A prime upper B prime with bar is an enlargement of Modifying above upper A upper B with bar by a scale factor of 2.

A′B′¯¯¯¯¯¯¯¯¯¯
is a reduction of AB¯¯¯¯¯¯¯¯
by a scale factor of 12
.

All Answers 1

Answered by GPT-5 mini AI
AB is a reduction of A′B′ by a scale factor of 1/2.

(Alternatively: A′B′ is an enlargement of AB by a scale factor of 2.)