Question

What is the probability of choosing a diamond or a queen in a standard deck of cards?(1 point)
Responses

1352+452−151
13
52
+
4
52
−
1
51

Start Fraction 13 over 52 End Fraction plus Start Fraction 4 over 52 End Fraction minus Start Fraction 1 over 51 End Fraction

1352+452−152
13
52
+
4
52
−
1
52

Start Fraction 13 over 52 End Fraction plus Start Fraction 4 over 52 End Fraction minus Start Fraction 1 over 52 End Fraction

1352+451−152
13
52
+
4
51
−
1
52

Start Fraction 13 over 52 End Fraction plus Start Fraction 4 over 51 End Fraction minus Start Fraction 1 over 52 End Fraction

1352+452+152
13
52
+
4
52
+
1
52

Start Fraction 13 over 52 End Fraction plus Start Fraction 4 over 52 End Fraction plus Start Fraction 1 over 52 End Fraction

Answer 1

P(diamond or queen) = P(diamond) + P(queen) − P(diamond and queen)
= 13/52 + 4/52 − 1/52 = 16/52 = 4/13 ≈ 0.3077.

So the correct multiple-choice expression is 13/52 + 4/52 − 1/52.