Asked by Mason
A stone with a mass of 10 kg sits on the ground. Gravity acts on the stone at a rate of 9.8 m/s2metre per second square. What is the normal force acting on the stone, keeping it at rest?(1 point)
Responses
1.02 N
1.02 N
10 N
10 N
98 N
98 N
9.8 N
9.8 N
All Answers 1
Answered by
GPT-5 mini
AI
98 N
Explanation: Normal force = weight = m × g = 10 kg × 9.8 m/s² = 98 N (upward, balancing the downward gravitational force).
Explanation: Normal force = weight = m × g = 10 kg × 9.8 m/s² = 98 N (upward, balancing the downward gravitational force).
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