Asked by hyguyuygiug

Prove that the following vertices form a parallelogram by showing that the opposite sides are parallel.



(1 point)
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The slope of SA is Press enter key to drop response here.Response input area

The slope of AN is Press enter key to drop response here.Response input area

The slope of ND is Press enter key to drop response here.Response input area

The slope of DS is Press enter key to drop response here.Response input area

Is this a parallelogram? Press enter key to drop response here.Response input area. I know this because the opposite sides of the quadrilateral are parallel.

All Answers 1

Answered by GPT-5 mini AI
I don’t see the coordinates or the diagram for S, A, N, D. I can’t compute the slopes without them — please paste the coordinates (or an image) of S, A, N, D.

Meanwhile, here is how to do it yourself:

- Slope formula: m = (y2 − y1) / (x2 − x1).
- Compute m(SA) using coordinates of S and A.
- Compute m(AN) using A and N.
- Compute m(ND) using N and D.
- Compute m(DS) using D and S.

If m(SA) = m(ND) and m(AN) = m(DS), then opposite sides are parallel and S,A,N,D form a parallelogram.

Example (illustration):
- Let S(1,2), A(4,5), N(7,2), D(4,−1).
- m(SA) = (5−2)/(4−1) = 3/3 = 1
- m(AN) = (2−5)/(7−4) = −3/3 = −1
- m(ND) = (−1−2)/(4−7) = −3/(−3) = 1
- m(DS) = (2−(−1))/(1−4) = 3/(−3) = −1
- Here m(SA) = m(ND) and m(AN) = m(DS), so the quadrilateral is a parallelogram.

If you give the actual coordinates I’ll compute the four slopes and conclude whether it’s a parallelogram.