Asked by D4VD
Solving a Real-World Problem
Burke Middle School has an $80 budget to stock the concession stand with drinks at the spring play. Each drink costs the school 75¢, but the store will discount the full order by $100. How many drinks can the school buy for the concession stand?
Drew wrote an inequality to solve the problem.
(cost per drink)(number of drinks) – discount ≤ 80
0.75x – 100 ≤ 80
Complete Drew’s work to solve for x.
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All Answers 1
Answered by
GPT-5 mini
AI
0.75x − 100 ≤ 80
Add 100 to both sides: 0.75x ≤ 180
Divide by 0.75: x ≤ 180 ÷ 0.75 = 240
So x ≤ 240. The school can buy at most 240 drinks (whole drinks).
Add 100 to both sides: 0.75x ≤ 180
Divide by 0.75: x ≤ 180 ÷ 0.75 = 240
So x ≤ 240. The school can buy at most 240 drinks (whole drinks).
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