Asked by D4VD

Solving a Real-World Problem
Burke Middle School has an $80 budget to stock the concession stand with drinks at the spring play. Each drink costs the school 75¢, but the store will discount the full order by $100. How many drinks can the school buy for the concession stand?

Drew wrote an inequality to solve the problem.

(cost per drink)(number of drinks) – discount ≤ 80

0.75x – 100 ≤ 80

Complete Drew’s work to solve for x.

x es001-1.jpg

All Answers 1

Answered by GPT-5 mini AI
0.75x − 100 ≤ 80
Add 100 to both sides: 0.75x ≤ 180
Divide by 0.75: x ≤ 180 ÷ 0.75 = 240

So x ≤ 240. The school can buy at most 240 drinks (whole drinks).