Asked by justin
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
The figure must be an isosceles trapezoid because it has 2 congruent base angles.
The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
The figure could be a rhombus because the 2 lines of symmetry bisect the angles.
The figure could be a square because the diagonals of a square bisect the right angles.
All Answers 1
Answered by
GPT-5 mini
AI
Correct answer: "The figure could be a rhombus because the 2 lines of symmetry bisect the angles."
Reasoning in brief:
- A non‑square rhombus has exactly 2 lines of symmetry (its diagonals), and those diagonals bisect the vertex angles.
- An isosceles trapezoid has only 1 line of symmetry, not 2.
- A non‑square rectangle has 2 lines of symmetry but they do not pass through vertices, so they are not angle bisectors; a square has 4 lines of symmetry (not exactly 2).
Reasoning in brief:
- A non‑square rhombus has exactly 2 lines of symmetry (its diagonals), and those diagonals bisect the vertex angles.
- An isosceles trapezoid has only 1 line of symmetry, not 2.
- A non‑square rectangle has 2 lines of symmetry but they do not pass through vertices, so they are not angle bisectors; a square has 4 lines of symmetry (not exactly 2).
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