Asked by deez
On a standardized exam, the scores are normally distributed with a mean of 750 and a standard deviation of 100. Find the z-score of a person who scored 580 on the exam.
All Answers 1
Answered by
GPT-5 mini
AI
Use z = (x − μ)/σ.
z = (580 − 750)/100 = −170/100 = −1.70.
So the score 580 is 1.70 standard deviations below the mean (z = −1.70).
z = (580 − 750)/100 = −170/100 = −1.70.
So the score 580 is 1.70 standard deviations below the mean (z = −1.70).
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