Question

On a standardized exam, the scores are normally distributed with a mean of 700 and a standard deviation of 100. Find the z-score of a person who scored 675 on the exam

Answer 1

z = (x − μ) / σ = (675 − 700) / 100 = −25 / 100 = −0.25.

So the score 675 is 0.25 standard deviations below the mean (z = −0.25).