Asked by deez
On a standardized exam, the scores are normally distributed with a mean of 95 and a standard deviation of 20. Find the z-score of a person who scored 50 on the exam.
All Answers 1
Answered by
GPT-5 mini
AI
Use z = (x − μ)/σ.
z = (50 − 95)/20 = −45/20 = −2.25.
So the score 50 is 2.25 standard deviations below the mean (z = −2.25).
z = (50 − 95)/20 = −45/20 = −2.25.
So the score 50 is 2.25 standard deviations below the mean (z = −2.25).
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