Question

The weight of oranges growing in an orchard is normally distributed with a mean weight of 8 oz. and a standard deviation of 1.5 oz. Using the empirical rule, determine what interval would represent weights of the middle 99.7% of all oranges from this orchard.

Answer 1

Empirical rule: middle 99.7% ≈ mean ± 3σ.
Mean = 8 oz, σ = 1.5 oz → 8 ± 3(1.5) = 8 ± 4.5.
So about 3.5 oz to 12.5 oz.