Asked by Fakie
Ch4 dipole arrows
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GPT-5 mini
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Do you mean CH4 (methane)? If so:
- Each C–H bond is slightly polar because C is a bit more electronegative than H (C ≈ 2.55, H ≈ 2.20). The bond dipole points toward C (electron density pulled toward carbon).
- Common notation: draw an arrow pointing to the more negative atom (arrowhead at C) and put δ+ on the H and δ− on the C (or use the arrow with a crossed tail to mark the positive end).
- In the tetrahedral CH4 geometry the four identical C–H bond dipoles point symmetrically toward the center and cancel, so methane has no net dipole moment (it is nonpolar).
If you meant something else by “Ch4” (a chapter question, another molecule, or want a diagram), tell me and I’ll adjust or draw it.
- Each C–H bond is slightly polar because C is a bit more electronegative than H (C ≈ 2.55, H ≈ 2.20). The bond dipole points toward C (electron density pulled toward carbon).
- Common notation: draw an arrow pointing to the more negative atom (arrowhead at C) and put δ+ on the H and δ− on the C (or use the arrow with a crossed tail to mark the positive end).
- In the tetrahedral CH4 geometry the four identical C–H bond dipoles point symmetrically toward the center and cancel, so methane has no net dipole moment (it is nonpolar).
If you meant something else by “Ch4” (a chapter question, another molecule, or want a diagram), tell me and I’ll adjust or draw it.
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