Question

What is the solution to the following system?
5x+2y+z=4
x+2z=4
2x+y-z=-1

x = 0, y = 1, z = 2
x = 1, y = –1, z = 2
x = 1, y = 0, z = –1
x = 2, y = 1, z = 0

Answer 1

x = 0, y = 1, z = 2

(Check: x + 2z = 0 + 4 = 4; 5x+2y+z = 0+2+2 = 4; 2x+y-z = 0+1-2 = -1.)